Question 9
Gravitational FieldA body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 × 103 km, g = 10 m s−2]
- A.14 km s−1
- B.13 km s−1
- C.12 km s−1
- D.11 km s−1
Show the answer and explanation
Answer: D (11 km s−1)
Explanation
Escape velocity v = √(2gR) = √(2 × 10 × 6.4 × 106) ≈ 1.13 × 104 m s−1, about 11 km s−1.