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JAMB Physics 1995 Question 10

Question 10

Equilibrium of Forces

A uniform rod PQ of length 1 m and mass 2 kg is pivoted at the end P. If a load of 14 N is placed at the centre of the rod, find the force that should be applied vertically upwards at Q to maintain the rod in equilibrium horizontally. [g = 10 m s−2]

  1. A.68 N
  2. B.28 N
  3. C.17 N
  4. D.7 N
Show the answer and explanation

Answer: C (17 N)

Explanation

The rod's weight (20 N) and the 14 N load both act at the centre, 0.5 m from P. Moments about P: F × 1 = 34 × 0.5, so F = 17 N.