passwella.
Menu

JAMB Physics 1995 Question 2

Question 2

Simple Harmonic Motion

The length of a displaced pendulum bob which passes its lowest point twice every second is [g = 10 m s−2]

  1. A.0.25 m
  2. B.0.45 m
  3. C.0.58 m
  4. D.1.00 m
Show the answer and explanation

Answer: A (0.25 m)

Explanation

Passing the lowest point twice each second means one full swing takes 1 s, so T = 1 s. From T = 2π√(L/g), L = gT2/(4π2) = 10/39.5 ≈ 0.25 m.