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JAMB Physics 1993 Question 3

Question 3

Motion

The diagram above shows a velocity-time graph representing the motion of a car. Find the total distance covered during the acceleration and retardation periods of the motion.

Diagram for this question
  1. A.75m
  2. B.150m
  3. C.300m
  4. D.375m
Show the answer and explanation

Answer: A (75m)

Explanation

Distance = area under the graph. Acceleration (0–10 s): ½ × 10 × 10 = 50 m. Retardation (40–45 s): ½ × 5 × 10 = 25 m. Total = 75 m.