Question 6
MotionIf a car starts from rest and moves with a uniform acceleration of 10 m s−2 for ten seconds, the distance it covers in the last one second of its motion is
- A.95 m
- B.100 m
- C.500 m
- D.905 m
- E.1000 m
Show the answer and explanation
Answer: A (95 m)
Explanation
Distance in 10 s = ½ × 10 × 10² = 500 m; in 9 s = ½ × 10 × 9² = 405 m. The last second covers 500 − 405 = 95 m.