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JAMB Physics 1984 Question 26

Question 26

Motion

A particle moves in a circular orbit of radius 0.02 m. If the speed of the particle is 0.88 m s−1, calculate its frequency in cycles per second.

  1. A.2.0
  2. B.7.0
  3. C.8.8
  4. D.14.0
  5. E.17.6
Show the answer and explanation

Answer: B (7.0)

Explanation

ω = v/r = 0.88/0.02 = 44 rad s−1. f = ω/2π = 44/(2 × 3.142) ≈ 7.0 Hz.