JAMB Physics 1984 Question 23

Question 23

Simple Harmonic Motion

A simple pendulum, 0.6 m long, has a period of 1.5 s. What is the period of a similar pendulum 0.4 m long in the same location?

  1. A.1.5√(2/3) s
  2. B.1.5√(3/2) s
  3. C.2.25 s
  4. D.1.00 s
  5. E.2.00 s
Show the answer and explanation

Answer: A (1.5√(2/3) s)

Explanation

T is proportional to √L, so T₂ = 1.5 × √(0.4/0.6) = 1.5√(2/3) s.