Question 21
Newton's Laws and MomentumA body of mass 5 kg initially at rest is acted upon by two mutually perpendicular forces 12 N and 5 N as shown in Fig. 3. If the particle moves in the direction QA, calculate the magnitude of the acceleration.
- A.0.40 m s−2
- B.1.40 m s−2
- C.0.26 m s−2
- D.2.60 m s−2
- E.3.40 m s−2
Show the answer and explanation
Answer: D (2.60 m s−2)
Explanation
Resultant force = √(12² + 5²) = 13 N. a = F/m = 13/5 = 2.6 m s−2.