Question 29
Equilibrium of ForcesA uniform beam PQ of mass 20 kg and length 5 m is balanced as shown (Fig. 8). A man of weight 800 N stands at M such that QM = 2 m. The reactions at P and Q respectively are (take g = 10 m s−2).

- A.300 N and 500 N
- B.420 N and 580 N
- C.220 N and 380 N
- D.580 N and 420 N
- E.380 N and 220 N
Show the answer and explanation
Answer: B (420 N and 580 N)
Explanation
Moments about P: 200 × 2.5 + 800 × 3 = Q × 5, so Q = 580 N. Then P = 1000 − 580 = 420 N.