Question 28
Scalars and VectorsA body is acted on by forces applied at points P and Q as shown (Fig. 7). Their resultant is equal to
- A.2√5 N in a direction N 56°E
- B.2√5 N in a direction N 56°W
- C.2√13 N in a direction N 56°E.
- D.2√13 N in a direction N 56°W
- E.√10 N in a direction N 56°E.
Show the answer and explanation
Answer: C (2√13 N in a direction N 56°E.)
Explanation
The 4 N (north) and 6 N (east) forces are at right angles: R = √(16 + 36) = √52 = 2√13 N. tan θ = 6/4 from north, θ ≈ 56°, so the direction is N 56°E.