Question 28
Current ElectricityA milliammeter of resistance 5 Ω and full scale deflection of 50 mA is to be used to measure a potential difference of 50 V. The resistance of the multiplier should be
- A.95 Ω
- B.110 Ω
- C.595 Ω
- D.995 Ω
- E.1005 Ω.
Show the answer and explanation
Answer: D (995 Ω)
Explanation
At full scale, 50 V must drive 0.05 A through the meter plus the multiplier: 50 = 0.05 × (5 + R), so 5 + R = 1000 and R = 995 Ω.