JAMB Physics 1978 Question 5

Question 5

Elasticity

A piece of rubber 10 cm long stretches 6 mm when a load of 100 N is hung from it. What is the strain?

  1. A.60
  2. B.6
  3. C.6 × 10−2
  4. D.6 × 10−3
  5. E.0.6
Show the answer and explanation

Answer: C (6 × 10−2)

Explanation

Strain = extension ÷ original length = 0.6 cm ÷ 10 cm = 0.06 = 6 × 10−2 (it has no unit).