JAMB Mathematics 2009 Question 8

Question 8

Logarithms

If log102 = 0.3010 and log107 = 0.8451, evaluate log10280.

  1. A.3.4471
  2. B.2.4471
  3. C.1.4471
  4. D.1.4071
Show the answer and explanation

Answer: B (2.4471)

Explanation

280 = 22 × 7 × 10, so log 280 = 2(0.3010) + 0.8451 + 1 = 2.4471.