Question 26
BearingsA ship sails a distance of 50km in the direction S50°E and then sails the distance of 50km in the direction N40°E. Find the bearing of the ship from its original position.
- A.S90°E
- B.N40°E
- C.S95°E
- D.N85°E
Show the answer and explanation
Answer: D (N85°E)
Explanation
The two legs (bearings 130° and 040°) are at right angles and equal, so the direct line makes 45° with the first leg. Its bearing is 130° − 45° = 085°, i.e. N85°E.