Question 27
Circle TheoremsIn the diagram above O is the centre of the circle. If SOQ is a diameter and ∠PRS is 38°, what is the value of ∠PSQ?

- A.148°
- B.104°
- C.80°
- D.52°
Show the answer and explanation
Answer: D (52°)
Explanation
Angle PQS = angle PRS = 38° (same segment). Angle SPQ = 90° (angle in a semicircle). So angle PSQ = 180° − 90° − 38° = 52°.