Question 7
Gas LawsIf sulphur (IV) oxide and methane are released simultaneously at the opposite ends of a narrow tube, the rates of diffusion RSO2 and RCH4 will be in the ratio [S = 32, O = 16, C = 12, H = 1]
- A.4:1
- B.2:1
- C.1:2
- D.1:4
Show the answer and explanation
Answer: C (1:2)
Explanation
Rate is inversely proportional to √(molar mass). R(SO2)/R(CH4) = √(16/64) = 1/2, so the ratio is 1 : 2.