Question 6
Mole Concept and StoichiometryA given amount of gas occupies 10.0 dm3 at 4 atm, and 273°C. The number of moles of the gas present is [Molar volume of a gas at s.t.p. = 22.4 dm3]
- A.0.89 mol
- B.1.90 mol
- C.3.80 mol
- D.5.70 mol
Show the answer and explanation
Answer: A (0.89 mol)
Explanation
Convert to s.t.p.: V = 10.0 × 4 × 273/546 = 20 dm3. Moles = 20/22.4 ≈ 0.89 mol.