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JAMB Chemistry 1997 Question 6

Question 6

Gas Laws

A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is

  1. A.0.90 atm
  2. B.0.80 atm
  3. C.0.70 atm
  4. D.0.60 atm
Show the answer and explanation

Answer: A (0.90 atm)

Explanation

Total moles = 0.70. Mole fraction of He = 0.30/0.70, so its partial pressure = (0.30/0.70) × 2.1 = 0.90 atm.