Question 23
ElectrolysisWhat volume of oxygen measured at s.t.p would be liberated on electrolysis by 9650 coulombs of electricity? [Molar volume of gas = 22.4 dm3, F = 96,500 C mol-1]
- A.22.4 dm3
- B.11.2 dm3
- C.1.12 dm3
- D.0.560 dm3
Show the answer and explanation
Answer: D (0.560 dm3)
Explanation
9650 C is 0.1 F. Making one mole of O2 needs 4 F (4OH− → O2 + 2H2O + 4e−), so 0.1 F gives 0.025 mol = 0.025 × 22.4 = 0.560 dm3.