Question 22
Mole Concept and Stoichiometry20 cm3 of a 2.0 M solution of ethanoic acid was added to excess of 0.05 M sodium hydroxide. The mass of the salt produced is [Na = 23, C = 12, O = 16, H = 1]
- A.2.50 g
- B.2.73 g
- C.3.28 g
- D.4.54 g
Show the answer and explanation
Answer: C (3.28 g)
Explanation
Moles of acid = 0.020 × 2.0 = 0.04 mol, giving 0.04 mol of CH3COONa (M = 82). Mass = 0.04 × 82 = 3.28 g.