Question 5
Circle TheoremsIn the diagram, O is the centre of the circle, if ∠QRS = 62°, find the value of ∠SQR.
- A.14°
- B.28°
- C.31°
- D.45°
- E.90°
Show the answer and explanation
Answer: B (28°)
Explanation
QR passes through O, so it is a diameter and ∠QSR = 90° (angle in a semicircle). Then ∠SQR = 180° − 90° − 62° = 28°.