Question 3
Mensuration of Plane ShapesIn the diagram, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of △QPT.
- A.39cm2
- B.28cm2
- C.24cm2
- D.21cm2
- E.19cm2
Show the answer and explanation
Answer: B (28cm2)
Explanation
Area QST = ½ × |TS| × 8 = 52, so |TS| = 13 cm. |PS| = |QR| = 6 cm, so |TP| = 7 cm. Area QPT = ½ × 7 × 8 = 28 cm².