Question 47
Circle TheoremsIn the diagram, Q, R and S are points on the circle centre O. If ∠QRS = 62°, find ∠SQR

- A.90°
- B.28°
- C.49°
- D.14°
Show the answer and explanation
Answer: B (28°)
Explanation
QR passes through O, so it is a diameter and ∠QSR = 90°. Then ∠SQR = 180° − 90° − 62° = 28°.