Question 37
Circle TheoremsIn the diagram, O is the centre of the circle QRS and ∠SQR = 28°. Find ∠ORS.

- A.76°
- B.62°
- C.56°
- D.28°
Show the answer and explanation
Answer: B (62°)
Explanation
The angle at the centre is twice the angle at the circumference: ∠SOR = 56°. Triangle SOR is isosceles (OS = OR), so ∠ORS = (180° − 56°)/2 = 62°.