Question 14
Algebraic ExpressionsMake x the subject of the relation: y = (ax3 − b)/3z
- A.x = ∛(3yzb/a)
- B.x = ∛((3yz + b)/a)
- C.x = ∛((3yz − b)/a)
- D.x = ∛((3y3 + b)/az)
Show the answer and explanation
Answer: B (x = ∛((3yz + b)/a))
Explanation
Multiply by 3z: 3yz = ax³ − b. Then ax³ = 3yz + b, x³ = (3yz + b)/a, and take the cube root.