Question 30
Circle TheoremsIn the diagram, O is the centre of circle PQRS, ∠PQR = 72° and OR ∥ PS. Find ∠OPS.

- A.18°
- B.108°
- C.54°
- D.36°
Show the answer and explanation
Answer: D (36°)
Explanation
∠POR = 2 × 72° = 144°, so in isosceles triangle OPR, ∠OPR = ∠ORP = 18°. ∠RPS = ∠ORP = 18° (alternate angles), so ∠OPS = 18° + 18° = 36°.