Question 41
Circle TheoremsIn the diagram, O is the centre of the circle, ∠QPS = 100°, ∠PSQ = 60° and ∠QSR = 80°. Calculate ∠SQR.

- A.20°
- B.40°
- C.60°
- D.80°
Show the answer and explanation
Answer: A (20°)
Explanation
∠QRS = 180° − 100° = 80° (opposite angles of cyclic quadrilateral). In triangle QRS, ∠SQR = 180° − 80° − 80° = 20°.