Question 36
Mensuration of Plane ShapesIn the diagram, MOPQ is a trapezium with QP//MO, MQ//NP, NQ//OP, |QP| = 9 cm and the height of ΔQNP = 6 cm, calculate the area of the trapezium.
- A.96 cm2
- B.90 cm2
- C.81 cm2
- D.27 cm2
Show the answer and explanation
Answer: C (81 cm2)
Explanation
MNPQ and NOPQ are parallelograms, so MN = NO = 9 cm and MO = 18 cm. Area = ½(18 + 9) × 6 = 81 cm².