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WAEC Mathematics 2015 Question 44

Question 44

Measures of Dispersion

Calculate the mean deviation of 5, 3, 0, 7, 2, 1.

  1. A.0.0
  2. B.2.0
  3. C.2.5
  4. D.3.0
Show the answer and explanation

Answer: B (2.0)

Explanation

Mean = 18/6 = 3. Deviations 2, 0, 3, 4, 1, 2 add to 12, so mean deviation = 12/6 = 2.0.