Question 18
Angles and PolygonsIn the diagram, PQ//RT, QR//SU, ∠PQR = 48° and ∠RTS = x. Find the value of x.

- A.134°
- B.132°
- C.96°
- D.48°
Show the answer and explanation
Answer: B (132°)
Explanation
∠QRT = ∠PQR = 48° (alternate angles, PQ//RT). Since QR//SU, ∠RTS and ∠QRT are co-interior, so x = 180° − 48° = 132°.