Question 44
Circle TheoremsIn the diagram, O is the centre of the circle, PR is a tangent to the circle at Q and ∠SOQ = 86°. Calculate the value of ∠SQR.

- A.43°
- B.47°
- C.54°
- D.86°
Show the answer and explanation
Answer: A (43°)
Explanation
OS = OQ, so ∠OQS = (180° − 86°)/2 = 47°. The radius OQ is perpendicular to the tangent, so ∠SQR = 90° − 47° = 43°.