Question 26
TrigonometryIf sin 3y = cos 2y and 0° ≤ y ≤ 90°, find the value of y.
- A.18°
- B.36°
- C.54°
- D.90°
Show the answer and explanation
Answer: A (18°)
Explanation
sin A = cos B when A + B = 90°: 3y + 2y = 90°, so y = 18°.
If sin 3y = cos 2y and 0° ≤ y ≤ 90°, find the value of y.
Answer: A (18°)
sin A = cos B when A + B = 90°: 3y + 2y = 90°, so y = 18°.