Question 35
Linear and Simultaneous EquationsSolve: (2x + 1)/6 − (3x − 1)/4 = 0.
- A.1
- B.1/5
- C.−1/5
- D.−1
Show the answer and explanation
Answer: A (1)
Explanation
Multiply by 12: 2(2x + 1) − 3(3x − 1) = 0, so 4x + 2 − 9x + 3 = 0, −5x = −5 and x = 1.
Solve: (2x + 1)/6 − (3x − 1)/4 = 0.
Answer: A (1)
Multiply by 12: 2(2x + 1) − 3(3x − 1) = 0, so 4x + 2 − 9x + 3 = 0, −5x = −5 and x = 1.