Question 3
LogarithmsIf log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log(28/3).
- A.2x + y − z
- B.2x + z − y
- C.x + y − 2z
- D.x + z − y
Show the answer and explanation
Answer: B (2x + z − y)
Explanation
28/3 = 22 × 7 ÷ 3, so log(28/3) = 2 log 2 + log 7 − log 3 = 2x + z − y.