Question 30
IndicesIf 2n = 128, find the value of (2n−1)(5n−2).
- A.5(106)
- B.2(106)
- C.5(105)
- D.2(105)
Show the answer and explanation
Answer: D (2(105))
Explanation
27 = 128, so n = 7. Then 26 × 55 = 2 × (2 × 5)5 = 2(105).
If 2n = 128, find the value of (2n−1)(5n−2).
Answer: D (2(105))
27 = 128, so n = 7. Then 26 × 55 = 2 × (2 × 5)5 = 2(105).