Question 38
TrigonometryPQRS is a rhombus of side 16 cm. The diagonal |QS| = 20 cm. Calculate, correct to the nearest degree, ∠PQR.
- A.51°
- B.64°
- C.77°
- D.103°
Show the answer and explanation
Answer: D (103°)
Explanation
Half of QS is 10 cm, so half of ∠QPS has sine 10/16, giving ∠QPS ≈ 77.4°. Adjacent angles of a rhombus add to 180°, so ∠PQR ≈ 103°.