Question 32
Circle TheoremsO is the centre of the circle PQRS. PR and QS intersect at T. POR is a diameter, ∠PQT = 42° and ∠QTR = 64°. Find ∠QRT

- A.68°
- B.64°
- C.42°
- D.32°
- E.22°.
Show the answer and explanation
Answer: A (68°)
Explanation
PR is a diameter, so ∠PQR = 90° and ∠TQR = 90 − 42 = 48°. In triangle QTR, ∠QRT = 180 − 64 − 48 = 68°.