Question 38
Triangles and QuadrilateralsThe trapezium PQRS has /PS/ = /PQ/, PQ is parallel to SR, <PQS = 34° and <SPQ = 2<SRQ. Find the size of <SQR

- A.58°
- B.68°
- C.78°
- D.90°
- E.112°
Show the answer and explanation
Answer: D (90°)
Explanation
PS = PQ, so <PSQ = 34° and <SPQ = 180° − 68° = 112°, which makes <SRQ = 56°. <QSR = <PQS = 34° (alternate angles), so in triangle SQR, <SQR = 180° − 34° − 56° = 90°.