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WAEC Mathematics 1995 Question 42

Question 42

Triangles and Quadrilaterals

In ΔABC above, BC is produced to D, |AB| = |AC| and ∠BAC = 50°: Find ∠ACD

Diagram for this question
  1. A.50°
  2. B.60°
  3. C.65°
  4. D.100°
  5. E.115°
Show the answer and explanation

Answer: E (115°)

Explanation

The base angles are equal: ∠ACB = (180° − 50°)/2 = 65°. Then ∠ACD = 180° − 65° = 115° (angles on a straight line).