passwella.
Menu

WAEC Mathematics 1994 Question 41

Question 41

Trigonometry

If sinθ = k, find tanθ, 0° ≤ θ ≤ 90°

  1. A.1 − k
  2. B.k/(k − 1)
  3. C.k/√(1 − k2)
  4. D.k/(1 − k)
  5. E.k/√(k2 − 1)
Show the answer and explanation

Answer: C (k/√(1 − k2))

Explanation

Take opposite = k and hypotenuse = 1; then adjacent = √(1 − k²), so tanθ = k/√(1 − k²).