Question 33
TrigonometryIf sin x = 12/13, where 0° < x < 90°, find the value of 1 − cos2x.
- A.25/169
- B.64/169
- C.105/169
- D.144/169
- E.8/13
Show the answer and explanation
Answer: D (144/169)
Explanation
1 − cos2x = sin2x = (12/13)2 = 144/169.
If sin x = 12/13, where 0° < x < 90°, find the value of 1 − cos2x.
Answer: D (144/169)
1 − cos2x = sin2x = (12/13)2 = 144/169.