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WAEC Mathematics 1991 (August) Question 39

Question 39

Probability

If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5,
P(X∪Y) is

  1. A.0
  2. B.2/15
  3. C.4/15
  4. D.11/15
  5. E.1
Show the answer and explanation

Answer: D (11/15)

Explanation

For mutually exclusive events P(X∪Y) = P(X) + P(Y) = 1/3 + 2/5 = 11/15.