Question 29
Circle TheoremsIn the diagram above, ATR is a tangent at the point T; to the circle centre O, if ∠TOB = 145°, find ∠TAO

- A.20°
- B.35°
- C.45°
- D.55°
- E.65°
Show the answer and explanation
Answer: D (55°)
Explanation
AOB is a straight line, so ∠AOT = 180° − 145° = 35°. The radius OT is perpendicular to the tangent, so ∠TAO = 180° − 90° − 35° = 55°.