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WAEC Further Mathematics 2019 Question 21

Question 21

Dynamics

A particle starts from rest and moves in a straight line such that its velocity, V ms−1, at time t second is given by V = 3t2 − 6t. Calculate the distance in 4 seconds.

  1. A.12 m
  2. B.16 m
  3. C.64 m
  4. D.96 m
Show the answer and explanation

Answer: B (16 m)

Explanation

s = ∫(3t² − 6t) dt = t³ − 3t² (s = 0 at t = 0). At t = 4, s = 64 − 48 = 16 m from the start.