Question 12
Indices and LogarithmsSolve log2(12x − 10) = 1 + log2(4x + 3).
- A.4.75
- B.4.00
- C.1.75
- D.1.00
Show the answer and explanation
Answer: B (4.00)
Explanation
log₂[(12x − 10)/(4x + 3)] = 1, so 12x − 10 = 2(4x + 3) = 8x + 6 and x = 4.
Solve log2(12x − 10) = 1 + log2(4x + 3).
Answer: B (4.00)
log₂[(12x − 10)/(4x + 3)] = 1, so 12x − 10 = 2(4x + 3) = 8x + 6 and x = 4.