WAEC Further Mathematics 2015 Question 31

Question 31

Dynamics

A particle starts from rest and moves in a straight line such that its acceleration after t seconds is given by a = (3t − 2) ms−2. Find the other time when the velocity would be zero.

  1. A.1/3 seconds
  2. B.3/4 seconds
  3. C.4/3 seconds
  4. D.2 seconds
Show the answer and explanation

Answer: C (4/3 seconds)

Explanation

v = 3t²/2 − 2t (v = 0 at t = 0). v = 0 again when 3t/2 = 2, t = 4/3 s.