WAEC Further Mathematics 2015 Question 3

Question 3

Indices and Logarithms

Solve 4(2x²) = 8x.

  1. A.1 and 2
  2. B.1 and −2
  3. C.−1 and 2
  4. D.−1 and −2
Show the answer and explanation

Answer: A (1 and 2)

Explanation

2^(2 + x²) = 2^(3x), so x² − 3x + 2 = 0, (x − 1)(x − 2) = 0: x = 1 or 2.