Question 17
IntegrationThe gradient of a curve at the point (−2, 0) is 3x2 − 4x. Find the equation of the curve.
- A.y = 6x − 4
- B.y = 6x2 − 4 + 12
- C.y = x3 − 2x2
- D.y = x3 − 2x2 + 16
Show the answer and explanation
Answer: D (y = x3 − 2x2 + 16)
Explanation
y = x³ − 2x² + k; through (−2, 0): −8 − 8 + k = 0, k = 16.