Question 17
DifferentiationThe radius of a sphere is increasing at a rate of 3 cm s−1, find the rate of increase in the surface area, when the radius is 2cm.
- A.8π cm2s−1
- B.16π cm2s−1
- C.24π cm2s−1
- D.48π cm2s−1
Show the answer and explanation
Answer: D (48π cm2s−1)
Explanation
A = 4πr², dA/dt = 8πr × dr/dt = 8π(2)(3) = 48π cm²/s.