Question 6
Indices and LogarithmsEvaluate log10(⅓ + ¼) + 2log102 + log10(3/7).
- A.−3
- B.0
- C.5/6
- D.1
Show the answer and explanation
Answer: B (0)
Explanation
⅓ + ¼ = 7/12. The sum is log10(7/12 × 4 × 3/7) = log101 = 0.
Evaluate log10(⅓ + ¼) + 2log102 + log10(3/7).
Answer: B (0)
⅓ + ¼ = 7/12. The sum is log10(7/12 × 4 × 3/7) = log101 = 0.